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空指针问题

feature/dangjian
zhangyuan 3 years ago
parent
commit
87b007fe5d
  1. 3
      esua-epdc/epdc-module/epdc-events/epdc-events-server/src/main/java/com/elink/esua/epdc/modules/item/service/impl/ItemServiceImpl.java
  2. 3
      esua-epdc/epdc-module/epdc-events/epdc-events-server/src/main/resources/mapper/item/ItemDao.xml

3
esua-epdc/epdc-module/epdc-events/epdc-events-server/src/main/java/com/elink/esua/epdc/modules/item/service/impl/ItemServiceImpl.java

@ -1314,7 +1314,7 @@ public class ItemServiceImpl extends BaseServiceImpl<ItemDao, ItemEntity> implem
List<ItemHandleProgressResultDTO> list = baseDao.selectListOfItemHandleProgressByMobile(itemId); List<ItemHandleProgressResultDTO> list = baseDao.selectListOfItemHandleProgressByMobile(itemId);
// 处理多次拼接处理人信息问题 // 处理多次拼接处理人信息问题
for (ItemHandleProgressResultDTO dto : list) { for (ItemHandleProgressResultDTO dto : list) {
String advice = dto.getAdvice(); String advice = dto.getAdvice() == null ? "" : dto.getAdvice();
// 对包含【h_s】的数据进行重新组装 // 对包含【h_s】的数据进行重新组装
if (advice.contains("h_s") && advice.contains(" 办理人:")) { if (advice.contains("h_s") && advice.contains(" 办理人:")) {
String hsStr = advice.substring(advice.indexOf("h_s")); String hsStr = advice.substring(advice.indexOf("h_s"));
@ -4025,6 +4025,7 @@ public class ItemServiceImpl extends BaseServiceImpl<ItemDao, ItemEntity> implem
/** /**
* 根据经纬度查询部门下附近项目数据 * 根据经纬度查询部门下附近项目数据
*
* @param params * @param params
* @return * @return
*/ */

3
esua-epdc/epdc-module/epdc-events/epdc-events-server/src/main/resources/mapper/item/ItemDao.xml

@ -1276,7 +1276,8 @@
AND img.DEL_FLAG = '0' AND img.DEL_FLAG = '0'
WHERE WHERE
hp.DEL_FLAG = '0' hp.DEL_FLAG = '0'
AND hp.ITEM_ID = #{itemId} UNION ALL AND hp.ITEM_ID = #{itemId}
UNION ALL
SELECT SELECT
item.ID, item.ID,
item.EVALUATION_TIME AS createdTime, item.EVALUATION_TIME AS createdTime,

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