解决查询树结构问题

epmet-module/data-aggregator/data-aggregator-server/src/main/java/com/epmet/dataaggre/dao/govorg/CustomerGridDao.java

@@ -48,4 +48,10 @@ public interface CustomerGridDao extends BaseDao<CustomerGridEntity> {
      * @Author sun
      */
     List<GridsInfoListResultDTO> selectGridByIds(@Param("gridIdList") List<String> gridIdList);
+
+    /**
+     * @Author sun
+     * @Description 根据组织Id查询当前组织下所有网格列表
+     **/
+    List<GridInfoResultDTO> selectGridListByAgencyId(@Param("agencyId") String agencyId);
 }

epmet-module/data-aggregator/data-aggregator-server/src/main/java/com/epmet/dataaggre/service/govorg/impl/GovOrgServiceImpl.java

@@ -60,7 +60,7 @@ public class GovOrgServiceImpl implements GovOrgService {
         returnDTO.setAgencyName(agencyEntity.getOrganizationName());
 
         //3:查询当前机关下的网格列表
-        List<GridInfoResultDTO> gridList = customerGridDao.selectAgencyGridList(agencyEntity.getId());
+        List<GridInfoResultDTO> gridList = customerGridDao.selectGridListByAgencyId(agencyEntity.getId());
         returnDTO.setGridList(gridList);
 
         //4:递归查询当前组织的下级组织以及每个下级组织对应的网格列表

epmet-module/data-aggregator/data-aggregator-server/src/main/resources/mapper/govorg/CustomerGridDao.xml

@@ -41,4 +41,15 @@
         )<!-- 按照foreach中遍历的Id顺序排序(按网格访问时间倒序) -->
     </select>
 
+    <select id="selectGridListByAgencyId" resultType="com.epmet.dataaggre.dto.govorg.result.GridInfoResultDTO">
+        SELECT
+            id AS "gridId",
+            grid_name AS "gridName"
+        FROM
+            customer_grid
+        WHERE
+            del_flag = '0'
+        AND pid = #{agencyId}
+    </select>
+
 </mapper>